Suppose the university bursar said that 600 student entered for business mathematics 300 entered for statistics while 173 students entered for both business mathematics and statistics how many student enrolled in the two courses altogether

The number of students who enrolled in business mathematics alone can be calculated by subtracting the number of students enrolled in both from the total number of students enrolled for business mathematics.

                                x = 600 - 173 = 427

In similar manner, we solve for the number of students enrolled for only statistics

                                 y = 300 - 173 = 127

The total number of students enrolled in two courses altogether is the sum of x and y and 173.

                                T = 427 + 127 + 173 = 727

Thus, all in all there are 727 students enrolled in the two courses.  

Hello! mark me brainliest
answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.

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