Claire has received scores of 85,88,87,and 85 on her algebra tests. what is the minimum score she must receive on the fifth test to have an overall test score average of at least 88?

88*5 = 440

 so all 5 tests need to equal at least 440

85 +88 +87 +85 = 345

440-345 = 95

 she needs at least a 95 to have an 88 average

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google