Which of the following is an extraneous solution of sqrt(-3x-2)=x+2 a.-6 b.-1 c.1 d.6

- 6 is the extraneous solution.

Step-by-step explanation:

Given : .

To find : Which of the following is an extraneous solution .

Solution : We have given that .

Taking square both sides

-3x - 2 = .

On applying identity   = a² + b² + 2ab

Then ,

-3x -2 =  x² + 2² + 2 * 2 *x

-3x -2 =  x² + 4 + 4x.

On adding both sides by 3x

-2 =  x² + 4 + 4x + 3x

-2 =  x² + 4 + 7x

On adding both sides by 2

0 =  x² + 4 + 7x + 2

On switching sides

x² +7x + 6 = 0

On Factoring

x² +6x + x + 6 = 0

x ( x+ 6 ) +1 (x +6 ) = 0

On grouping

( x +1) ( x +6) = 0

x = -1, -6.

Let check for x = -6

.

4 =  -4

An extraneous solution is a root of a transformed equation that is not a root of the original equation.

Therefore,  -6 is the extraneous solution.

hi i’m going tomorrow morning and i can come over and you out with this stuff for me haha ya day is going crazy and i’ll tell you what i’m talking about you don’t wanna go do you think i’m going to be a good friend i just don’t know how much you mean about the stuff you want to do and stuff you know i just want you and you know that i’m going crazy i don’t think i’m going crazy about going tomorrow and i’ll tell ya hey i don’t think i’m going crazy about going tomorrow and i’ll tell you what i’m done

why are you giving so many marks make your marks less and make a question list so that i can understand your question very nicely