Apolynomial function, f(x), with rational coefficients has roots of –2 and square root of 3. the irrational conjugates theorem states that which of the following must also be a root of the function?

if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

Step-by-step explanation:

Given : A polynomial function, f(x), with rational coefficients has roots of –2 and square root of 3.

To find :  which of the following must also be a root of the function?

Solution : We have root of  f(x)  = 2 +√3.

By the  irrational conjugates theorem : it state that  states that if   a + √b is an irrational root to a polynomial, then its irrational conjugate a - √b is also

root.

Therefore, if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.