Jessica attains a height of 4.7 feet above the launch and landing ramps after 1 second. her initial velocity is 25 feet per second. find the angle of her launch. a. which equation can you use with the given information to solve for ?

To answer this question, we convert first the given height and velocity to SI units so we could more comfortably use the equation. The conversion factor to be used is 1 m = 3.28 ft
    Height = 4.7 ft x (1 m/ 3.28 ft) = 1.43 m
    Velocity = 25 ft / s x (1 m / 3.28 ft) = 7.62 m/s

The maximum height that can be attained by an object following a projectile path is calculated through the equation,
     H = (v₀²)(sin²θ) / 2g
where v₀ is the initial velocity, H is the maximum height and g is the acceleration due to gravity. 

Transforming the equation to calculate for θ,
        sinθ = sqrt ((H)(2g) /(v₀²))
        sinθ = sqrt ((1.43)(2)(9.8)) / (7.62²))
        sinθ = 0.76

We calculate for the angle by getting the arcsin.
        sin⁻¹ (0.76) = 49.46°

ANSWER: 49.46°