Given the vertices of ∆abc are a (2,5), b (4,6) and c (3,1), find the vertices following each of the transformations from the original vertices:
a. rx-axis

b. ry = 3

c. t< -2,5>

d. t< 3,-6>

e. r(90◦, o)

a)

Reflection over x-axis.

We know that when any point is reflected over the x-axis, then the rule of transformation that is applied is:

               (x,y) → (x,-y)

Hence,

         A (2,5)→ A'(2,-5)

         B (4,6) → B'(4,-6)

and  C (3,1) → C'(3,-1)

b)

 Reflection about the line y=3

We know that any point after reflection is at a fixed distance from the line as it was before reflection.

Hence,

         A (2,5)→ A'(2,1)

         B (4,6) → B'(4,0)

and  C (3,1) → C'(3,5)

c)

T<-2,5>

The rule that is applied to this translation is:

         (x,y) → (x-2,y+5)

Hence,

         A (2,5)→ A'(0,10)

         B (4,6) → B'(2,11)

and  C (3,1) → C'(1,6)

d)

                    T<3,-6>

The rule that is applied to this translation is:

                  (x,y) → (x+3,y-6)

Hence,

         A (2,5)→ A'(5,-1)

         B (4,6) → B'(7,0)

and  C (3,1) → C'(6,-5)

e)

    r(90◦, o)    

It is  a rotation of a point 90 degree clockwise about the origin.

Hence, the rule that describes this transformation is:

           (x,y) → (y,-x)

Hence,

         A (2,5)→ A'(5,-2)

         B (4,6) → B'(6,-4)

and  C (3,1) → C'(1,-3)

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step-by-step explanation:

it is c, trust i got your back lol

step-by-step explanation: