Find the surface area of each figure to the nearest tenth. show your work, !

A. The figure given in A is a square pyramid and the formula for the surface area of this figure is:

A = l w + l sqrt [(w/2)^2 + h^2] + w sqrt [(l/2)^2 + h^2]

where l and w are the lengths of the base and h is the height of the pyramid. Since the base is square, so:

l = w = 16 in

h = 15 in

Substituting:

A = 16 * 16 + 16 sqrt [(16/2)^2 +15^2] + 16 sqrt [(16/2)^2 + 15^2]

A = 256 + 272 + 272

A = 800 in^2

B. We are given a cone, the formula for surface area is:

A = πr (r + h^2 + r^2)

where h is the height = 8 in and r is the radius = 3 in

Substituting:

A = π * 3 (3 + sqrt (8^2 + 3^2))

A = 34.63π in^2 = 108.80 in^2 

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116