Suppose s and t are mutually exclusive events. find p(s or t) if p(s) = 65% and p(t) = 7%.

a. 4.55%
b. 72%
c. 58%
d. 455%

P(S\cup T)=72%

Step-by-step explanation:

We are given that S and T are mutually exclusive events.

Therefore, the intersection of both the events must be 0.

i.e.

P (S) = 65% and P(T) = 7%

We know that P(S or T)=

Hence, P(S\cup T)=72%

1/5^2 = 7.56/45