The velocity of sound in air is given by the equation , where v is the velocity in meters per second and t is the temperature in degrees celsius. find the temperature when the velocity is 329 meters per second by graphing the equation. round the answer to the nearest degree. show your work.

The equation of velocity of sound in air is v = 20 √(273 + t). In this problem, we need to find the temperature when the velocity is 329 meters/s. You need to measure the time it takes a sound to travel a measured distance in order to measure its speed in air.

Given:

Velocity of sound in air equation = v = 20 √(273 + t)

Velocity = 329 m/s

To solve:

V = 20 √(273 + t)

329 = 20 * sqrt(273 + t)

16.45 = sqrt(273 + t)

273 + t = 16.45^2

t- 16.45^2-273

t = -2.4 degrees Celsius

So, the temperature when the velocity is 329 meters per second is -2.4 degrees Celsius.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

is there more to this question?