Oq is a diagonal of quadrilateral nopq. if noq=pqo, no = 5x + 12, and pq = 7x – 8, find the length of no for which nopq is a parallelogram.
a. 10
b. 24
c. 47
d. 62

Since it is a parallelogram, NO = PQ

5 x + 12 = 7 x - 8

12 + 8 = 7 x - 5 x

20 = 2 x

x = 20 : 2

x = 10

NO = 5 * 10 + 12 = 50 + 12 = 62

62

Hope this helps, have a BLESSED and wonderful day, as well as a safe one! Also, have a merry Christmas!  :-)

-Cutiepatutie

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.