Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assume that the population does not exhibit a normal distribution. weight lost on a diet: 95 % confidence n equals 51 x overbar equals 3.0 kg s equals 5.8 kg what is the confidence interval for the population mean mu ?

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

At 95% confidence level, the value of z is equivalent to:

z = 1.96

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

based on context clues you gave i'm assuming the answer would be c.