Mathematics, 28.01.2020 20:00 jaaiphieaslade

Which is the graph of f(x) = 100(0.7)x?

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Answer from: thebomb2023

I'm assuming the function is f(x) = 100(0.7)^x. This is the same as y = 100(0.7)^x because y = f(x).

Plug in x = 0 to get
y = 100(0.7)^x
y = 100(0.7)^0
y = 100(1)
y = 100
So (x,y) = (0,100) is one point on this function curve

Plug in x = 2 to get
y = 100(0.7)^x
y = 100(0.7)^2
y = 100(0.49)
y = 49
So (x,y) = (2,49) is another point on this curve

In summary, the two points on this function curve are (0,100) and (2,49)

Answer from: martinbricein10

The graph of f(x) passes through (0,100) points (2,49)

So option (a) is correct

We have to identify that out of the following given graphs which graph represents the function

$\rm f(x) = 100\times (0.7)^x$

The given graphs pass through two points . If the graph passes through a point , the point will satisfy the equation of graph. The points can be determined on observing from the graphs we can plug in the x coordinates

on putting x =0 in to the given function we get

$\rm f(0) = 100\times 0.7^{0} = 100$

So the graph of f(x) passes through (0,100)

Also putting x = 2 in the function equation we get

$\rm f(2) = 100\times (0.7)^{0.2} = 49$

So the also passes through (2,49)

The graph of f(x) passes through (0,100) points (2,49)

So option (a) is correct

For more information please refer to the link below

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Answer from: Quest

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

Find the composition of transformations that map abcd to ehgf. !

Answer from: Quest

Answer

1 number

explanation

if we use a graphing calculator, there is only one such number $c\in[0.5,0.75]$ that satisfies the conclusion of the mean value theorem, that is, a number $c\in[0.5,0.75]$ such that

$f'(c) = \dfrac{f(0.75) - f(0.5)}{0.75-0.5},$

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

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