Find all complex solutions of 2x^2+3x+6=0

To calculate the roots or the solution of the equation, we can use the quadratic formula:

x = [- b ± sqrt (b^2 – 4 a c)] / 2 a

where the coefficients are:

a = 2

b = 3

c = 6

Therefore substituting this into the equation:

x = [- 3 ± sqrt (3^2 – 4 * 2 * 6)] / 2 (2)

x = -0.75 ± [sqrt (9 – 48)] / 4

x = -0.75 ± [sqrt (-39)] / 4

x = -0.75 ± 0.25 i * sqrt (39)

x = -0.75 ± 0.25 i * (6.24)

x = -0.75 ± 1.56 i

Therefore the complex solutions are:

x = -0.75 ± 0.25 i * sqrt (39)

or

x = -0.75 ± 1.56 i

john has 55 candy left.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b