F(x) = 2x – 1 and g(x) = x2 – 3x – 2, find (f + g)(x)
a. (f + g)(x) = x2 – x – 3
b. (f + g)(x) = x – 3
c. (f + g)(x) = –x – 3
d. (f + g)(x) = x2 + 5x + 3

Correct option is:

A. (f + g)(x) = x² – x – 3

Step-by-step explanation:

We are given:

f(x) = 2x – 1 and g(x) = x² – 3x – 2

We have to find (f+g)(x)

(f+g)(x)=f(x)+g(x)

          = 2x -1 + x² - 3x - 2

          = x² +x(2-3) -1-2

          = x² -x -3

Hence, Correct option is:

A. (f + g)(x) = x² – x – 3

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743