Abox contains cards number 1-10. a card is drawn at random, then replaced, and a second card is drawn. what is the probability that the first number is a multiple of 5 and the second number is prime?

You would solve this by determining how many numbers from 1-10 can be multiples of 5.  That's obviously 5 and 10.  So that's 2/10 or reduced to 1/5.  Now the second question you have to find how many numbers from 1-10 are prime.  Prime is a number that can only be divided by 1 and itself.  So that would leave you with 1, 3, 5, 7.  I think where the trick comes into play is if you drew a 5 or 10 the first time, then you didn't place those cards back in the box, you couldn't draw them again.  So the answer would 4/10 or 2/5 if you could draw the 5 again.  Or I supposed if you had drew the 10 the first time and not the 5.  I assume however, they want you to exclude 5 and 10 because it was part of the first section of this equation.  So that would mean only 1, 3, and 7 or 3/10.

7days is 168 hours in decimal form it is just 168 there is no decimal form for this because it is like 168.0 and there is no number you are dividing it by for it to be a decimal.hope this