What values of b satisfy 4(3b + 2)2 = 64?
a. b = 2/3 and b = –2
b. b = 2 and b = 10/3
c. b = 2/3 and b = 3
d. b = 2 and b = -10/3

Assuming yo meant
4(3b+2)²=64

divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2

A is answer

Um what? rephrase that ?