Factor completely 3x ^2 -27

Both terms are multiply of 3, so you can factor 3 out;

3(x² - 9)

Now, we can see that x² - 9 is difference of two perfect squares

Recall that a² - b² = (a+b)(a-b)

So we have x²-9 = (x+3)(x-3)

So we can factor more here; 3(x²-9) = 3(x+3)(x-3)

Final  3(x+3)(x-3)

Iwould say rat and vsu but i’m not 100% sure