What is the weight (in grams) of a liquid that exactly fills a 163.5 milliliter container if the density of the liquid is 0.492grams over milliliter? round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

m = ρ v

m = (0.492 g / mL) * 163.5 mL

m = 80.442 g

rounded to nearest hundredth:

m = 80.44 g

80.44 grams

Step-by-step explanation:

We have to calculate the weight ( in grams ) of a liquid that exactly fills a 163.5 milliliter container if the density of the liquid is 0.492 grams over milliliter.

The formula to find density

ρ

ρ = Density

m = mass

v = volume

To find mass (weight), we will rewrite the equation in terms of m

m = ρ × v

m = 163.5 × (0.492g/ml)

m = 80.442 grams ≈ 80.44 grams

The weight of a liquid  is 80.44 grams that fills a container.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

correct answer is b. 27/8

step-by-step explanation: