Find the vertex, focus, directrix, and focal width of the parabola. x = 10y^2

vertex will be (0,0)

the stand form will be x/10=Y^2

the directrix is x=10

focus is (x+p,y)  (1/40,0)

w=1/10

Vertex will be (0,0),  the directrix is x=-1/40

the focus is (1/40, 0)

1/10 is focal width

Step-by-step explanation:

Vertex will be (0,0), and the parabola will open to the right.

The standard form will be x/10 = y^2, so we know that 4p = 1/10, and that p = 1/40.

Your directrix will be x=0-p, so the directrix is x=-1/40

The focus is (x+p, y), so the focus is (1/40, 0)

At x = 1/40, y^2 = 1/400, so y = +/- 1/20.  So 1/2 your width is 1/20.  2*(1/20) = 1/10 is your width at the focus.

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: