Find the area of a triangle with legs that are: 9 mm, 6 mm, and 12 mm.

Step-by-step explanation:

By Heron's formula ,the area of a triangle is given by :-

, where s is semi-perimeter of triangle and a,b ,c are the sides of the triangle.

Given : a=9 mm, b=6 mm, and c=12 mm.

Then , semi-perimeter:

Now, the area of triangle will be :-

2/3

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752