Mathematics, 10.01.2020 12:31 kealinwiley
A(n)=−6+3(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 6, plus, 3, left parenthesis, n, minus, 1, right parenthesis find the 16^\text{th}16 th 16, start superscript, t, h, end superscript term in the sequence.
Answers: 1
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A(n)=−6+3(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 6, plus, 3, left parenthesis...
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