Ten slips of paper numbered 1 thround 10 are place in a bag you draw a slip at random and draw another without replacing the first find the probability that both numbers are odd

We are given the numbers {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

So we have 5 odd numbers, and 5 even.

The probability of drawing an odd number is 5/10=0.5

The probability that the second drawing is odd is 4/9=0.444, since now there are 4 odd numbers left (one being drawn) and 9 in total.

Thus, the probability of both drawn numbers being odd is 0.5*0.444=0.222

0.222