Given a circle with endpoints of a diameter at –10 – 1i and 6 + 11i, answer the questions below. 1. the center of the circle is

The given endpoints which are in imaginary number can be written in Cartesian coordinates form as:

–10 – 1 i = (- 10, - 1)

6 + 11 i = (6, 11)

Since we know that these are the endpoints of the diameter, then this must mean that the center of the circle is the point located in the middle of the endpoints. So we use the middle distance formula to calculate for the coordinates of the center:

x = (-10 + 6) / 2 = - 4 / 2 = -2

y = (- 1 + 11) / 2 = 10 / 2 = 5

So the center is located at:

(- 2, 5)

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step-by-step explanation:

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step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.