What is the step by step way to solve this exponential equation? 2^(x+1)=3^x

2⁽ˣ⁺¹⁾ = 3ˣ

ln[2⁽ˣ⁺¹⁾] = ln(3ˣ)

(x+1).ln(2) = x.ln(3)
Expand:

x.ln(2) + ln(2) = x.ln(3)

x.ln(2) - x.ln(3) = - ln(2)

x[ln(2) - ln(3)] = - ln(2)

x = [ - ln(2)] / [ln2) - ln(3)

And x = 1.7095

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.