Rays ab and bc are perpendicular. point d lies in the interior of angleabc. if angleabd=3r+5 and angledbc=5r-27, find angleabd and angledbc.

The first step is to always illustrate the problem as shown in the attached picture. Lines AB and BC are perpendicular, meaning they for right angles with each other. Then, draw a random point D within angle ABC, then connect it towards vertex B. Two angles are formed with the following measurements in terms of r. To solve this problem, we apply Angle Addition Postulate. It states that the included angles within the whole angle, could sum up to the whole angle. Therefore, ∠ABD and ∠DBC should sum up to 90°.

∠ABC = ∠ABD + ∠DBC
90° = (3r + 5) + (5r - 27)
90 = 3r + 5 + 5r - 27
90 = 8r -22
8r = 112
r = 112/8
r = 14

Knowing r, we could substitute this to individual angle measurements given.

∠ABD = 3(14) + 5
∠ABD = 47°

∠DBC = 5(14) - 27
∠DBC = 43°

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%