Arectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 7272 yards, what are its dimensions? let w be the width and l the length of the athletic field. then l = nothing. recall that the formula of the perimeter: p = 2l+ 2w. which of the following is true about the perimeter 7272 of the athletic field? a. 7272 = 2(2w) + 2w b. 7272 = 2w + 2w c. 7272 = 2(2w) + w d. 7272 = 2w + w the width of the athletic field is nothing yards, and its length is nothing yards.