Charlie has a piece of toast that has cream cheese on one side, and he dropped it once. one time, it landed with the cream cheese side up. if he drops it 2 more times, what is the probability that it will have landed cream cheese side up a total of 3 times? (1 point)

Probability of landing  cream cheese side up 3 times is tex]\frac{1}{4}[/tex]

Step-by-step explanation:

The probability of getting cheese side up is one half (.

And this probability does not depend on the result of the last time you dropped it or the result before that.

So every time you drop a piece of toast the probability of getting cheese side up is one half (.

Charlie has already dropped it once (1st time) and it landed on cream cheese side up. So probability for this is 1 because it has already happened.

Next time (2nd time) he drops, the probability of landing cream cheese side up is

When he drops the piece of toast again (3rd time) the probability of landing cheese side up is again .

So the probability of landing  cream cheese side up 3 times is,

=

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

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step-by-step explanation: