Identify the vertical asymptotes of f(x) = 2 over quantity x squared plus 3 x minus 10.

First, simplify it, factor out any ones in the numerator and dennomenator


no common factors so move to next step

set the denomenator equal to 0 because that is where the function is undefined (we can't divide by 0)

x²+3x-10=0
factor
(x-2)(x+5)=0
set to zero

x-2=0
x=2

x+5=0
x=-5

vertical assemtotes are at x=-5 and x=2

Igot 108 hope that’s right !

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