Aregular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface area of 57 square centimeters. what is the surface area of the regular triangular pyramid?

57 cm^2 is equal to the lateral surface area, or the three sides in this case.

57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.

19+57= 76 cm^2 for sides+ base (total surface area)

Final 76 cm^2

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How much is 32 out of 40 written as a percentage? convert fraction (ratio) 32 / 40 answer:   80%