The football fields at three different schools were measured, and it was found that their perimeters were 320 m, 360 m, and 400 m. if the sutdents at each school are to run the same distance, and this must be a whole number of laps, what is the shortest distance they need to run?

Let us say that,

A = perimeter of football field of the 1st school

B = perimeter of football field of the 2nd school

C = perimeter of football field of the 3rd school

So that:

A = 320 m

B = 360 m

C = 400 m

So the first thing we have to do to find for the minimum laps to make is to divide every perimeter by the smallest one, therefore divide all by 320 m, hence:

A’ = 1

B’ = 1.125

C’ = 1.25

Now multiply everything by a number such that all laps will be a whole number, in this case multiply everything by 8:

A’ = 8

B’ = 9

C’ = 10

Hence the laps to run are:

8, 9 and 10

the answer is b i just did that

step-by-step explanation:

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .