The sum of 4 consecutive integers is 222. find the integers

The integers are 54, 55, 56 and 57

Let the integers be n, n + 1, n + 2 and n + 3.

Since the sum of the integers equals 222, we have that

n + n + 1 + n + 2 + n + 3 = 222

Collecting like terms, we have

n + n + n + n + 1 + 2 + 3 = 222

Simplifying, we have

4n + 6 = 222

Subtracting 6 from both sides, we have

4n + 6 - 6 = 222 - 6

4n = 216

Dividing both sides by 4, we have

n = 216/4

n = 54

Since n = 54, the first integers is 54

The second integer is n + 1 = 54 + 1 = 55,

The third integer is n + 2 = 54 + 2 = 56 and

The fourth integer is n + 3 = 54 + 3 = 57

So, the integers are 54, 55, 56 and 57

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222/4 = 55.5

take the 2 whole numbers below and above that

54 +55 +56 +57 = 222

14

step-by-step explanation:

the weight of the object inside the box!