![\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot sin(88^o)}{39.9}=sin(A) \\\\\\ sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right] \\\\\\ sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=\measuredangle A \\\\\\ 50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o](/tpl/images/0310/2132/85ce9.png)
The cosine law
how do i figure out which formula i'd use for this question?
b...
Mathematics, 11.10.2019 12:20 cam1295
The cosine law
how do i figure out which formula i'd use for this question?
b= 88 degrees, a= 31.5m, c= 25.6, b= 39. 9
Answers: 3
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