Find the equation of the tangent line of f^-1(x) at the point where it intersects the x-axis

Hello : 
note :
 1 )     f(X0) = Y0  equiv : X0 = f^-1(Y0)
 2 )     ( f^-1(Y0) )' = 1/ f'(X0)
in this exercice : X0 = 0
he equation of the tangent line  for graph of : f 
Y - Y0 = f'(X0) (X- 0)
sp : he equation of the tangent line  for graph of : f^-1(x)  is : 
X -X0 = f'(Y0) (Y -0)