Answer and solve, showing the steps you took

We apply the concept of calculus here. You can determine the minimum or maximum in here if you take the derivative of a function and equate it to zero. The solution is as follows:

n = 20t² - 20t +120
dn/dt = 0 = 40t - 20 + 0
40t - 20 = 0
40t = 20
t = 20/40
t = 1/2 or 0.5

Therefore, the number of bacteria would be minimal at 0.5°C.

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