Arectangle has length 12 feet and width 8 feet. every dimension of the rectangle is multiplied by 3/4 to form a similar rectangle. how is the ratio of the areas related to the ratio of corresponding side

Let the area of the original rectangle be A₁.

A₁ = (12 ft)(8 feet) = 96 ft²

To determine the area of the reduced triangle, let's compute the new dimensions first.

Length = 12 ft * 3/4 - 9 ft
Width = 8 ft *3/4 = 6 ft

Thus, the area of the new rectangle denoted as A₂ is
A₂ = (9 ft)(6 ft) = 54 ft

The ratio of the areas are:
A₂/A₁ = 54/96 = 9/16
The ratio of the sides are given to be 3/4.
Finally the ratios of the area to side would be:
Ratio = 9/16 ÷ 3/4 = 3/4

Therefore, the ratio of the areas is 3/4 of the ratio of the corresponding sides.

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post