How do i graph this? i have to find x and y intercepts and the vertex? ?

Set y=0 for the x intercepts, so expanding it we get x^2+4x+4+5=0 and x^2+4x+9 =0. Using the quadratic formula, we get that x= (-4+-sqrt(16-36))

right here, we see that the square root of something would be negative, so there are no x intercepts.

for the y intercepts, we set x=0 to get 2^2-5=-1.

for the vertex, we use x^2+4x+9 and -b/2a=the x value of the vertex =-4.

Plugging -4 into it, we get -16+16+9=9 for the y value of the vertex, getting (-4,9). Since -1 from (0, -1) is smaller than 9, the parabola forms a frowny face and goes downwards. Plug some random points in, and you'll have it down!

Byou start by adding them all and setting them equal to 180 since that is half of the total degrees in a circle.(2x+8) + (3x-14) + (3x-14) = 1808x-20 = 1808x = 200x = 25