Aconstruction company estimates the volume of concrete to pour in a house foundation with rectangular slab containment sized as: length = 18.30 +/- 0.02 m; width = 12.20 +/- 0.02 m; height = 0.50 +/- 0.05 m. calculate the uncertainty of the necessary volume of concrete, and the amount that would not fall short for the job.

IF the estimates are 100% accurate, then the maximum volume of concrete is the product of the maximum dimensions, namely
Vmax=18.32*12.22*0.55=123.13 m^3
and the minimum volume of concrete is the product of the minimum dimensions
Vmin=18.28*12.18*0.45=100.19 m^3
the uncertainty is therefore 123.13-100.19=22.94 m^3

On the practical side, to this uncertainty must be added to 
- squareness of the formwork
- evenness of the surface of the crushed stones on which the foundation sits on
- excess of concrete delivered by the truck
- volume of air bubbles trapped in the the concrete, ...

Ibelieve the total for the tip could be $21.90

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.