Plz

ally has 3 positive integers. she adds their reciprocals and gets a sum of 1. what is the product of her integers.

The integers are x,y,z

their reciprocals are , , and

the sum is 1
hmm
remember, a/a=1 when a=a




therefor
yz+xz+xy=xyz
doesn't help much

different integers
ah, hum
the only way I can see is trial and error

find 1/x for x=2,3,4,5,6,7,8,9, etc and evaluate
1/2=0.5
1/3=0.3333
1/4=0.25
1/5=0.2
1/6=0.166666666
1/7=0.14285714285714285714285714285714
1/8=0.125
1/9=0.11111111111
1/10=0.1
1/11=0.090909090909090909
hum, experimentation tells us that  it's probably not going to be 1/7
try adding the numbers and see which ones add to 1
hmm
ah ha

1/2+1/3+1/6=3/6+2/6+1/6=6/6=1

the integers are 2,3,6
their product is 2*3*6=36

There is no question, there is just the answer.