Use addition to solve the linear system of equations. 2x+y=5 3x+2y=4

2x+y=5 eq 1
3x+2y=4 eq2

now, multiply eq1 with -2
-2(2x+y=5)
== -4x-2y=-10eq 3
 
Add eq2 and eq3,
(3x+2x)+(-4x-2y)= 4+(10)
3x+2y - 4x-2y = -6
Cancel +2y and -2y we get,
3x-4x=-6
-x=-6 
therefore, x=6

Substitute value of x in eq1, 2x+y=52(6) + y=52(6) + y=512+y=5
y=5-12=-7

 x=6 and y=-7y