Out of 1,100 discs tested, 13 are defective. estimate the number of defective discs in a batch of 41,000. a. about 485 discs b. about 970 discs c. about 4,850 discs d. about 49 discs

Sample size={1,100 discs) = all possible outcomes
P(defective discs) = 13/1100 = 0.0118
Expected number of defects over a lot of 41,000  is:

41,000 x P(defects) = 41,000 x 0.0118 = 485.5 ≈ 485 (Answer A)

Iwould like to think so. what’s the question you need with?