What is the product of (p3)(2p2 - 4p)(3p2 - 1)?
a) 6p7 + 4p4
b) 6p7- 2p5 - 12p5 + 4p3
c) 6p7 - 12p6 - 2p5 + 4p4
d) 6p12 - 14p6 + 4p3

Answer

Find out the product of ( p³)(2p² - 4p)(3p² - 1) .

To prove

The expression given in the question

=  ( p³) × (2p² - 4p) × (3p² - 1)

First multiply first two terms

=  ( p³ × 2p² - p³ × 4p)(3p² - 1)

Now using the exponent property

Again multiply the terms

Therefore the option (C) is correct.

answer: check all that apply, where the options?

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.