Consider a triangle with vertices at s(-2,-3), a(2,3), and n(5,-4).
part a: what is the shortest side of the triangle? select the correct response.
a. line sa
b. line an
c. line ns
d. all sides are congruent.
part b: justify your answer from part a.

Step-by-step explanation:

Given that a triangle has vertices S(-2,-3), A(2,3), and N(5,-4)

To find side lengths we can use distance formula between two vertices

SA =

AN=

NS

Thus comparing we find that side NS is the shortest side

Option C is right answer

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right