De bisects ab at c. if ac =8x-23 and cb=3x+22 find x

x = 9.

Step-by-step explanation:

Given  : DE bisects AB at C. If AC =8x-23 and CB=3x+22.

To find :  Find X.

Solution : We have given  DE bisects AB at C.

Bisector : A point which cut the line in to two equal parts.

ACB

AC = CB . ( C  bisect AB)

Plug the values.

8x - 23 = 3x + 23 .

On subtracting both sides by 3x

8x - 23 - 3x  = 22 .

5x - 23 = 22 .

On adding both sides by 23 .

5x = 23 +22 .

5x = 45 .

On dividing both sides by 5 .

x = 9.

Therefore, x = 9.

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step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !