Afreight train leaves a station at noon traveling at 30 mph. a passenger train leaves 1 hour later traveling at 50 mph. at what time will the passenger train overtake the freight train?

after 2.5 hour passenger train would overtake .

Step-by-step explanation:

A freight  train leaves a station at noon traveling at 30 mph.

A passenger train leaves 1 hour later travelling at 50 mph

Let the time to leave the station of freight train = t

time to leave passenger train = t - 1

Since distance = speed × time

the expression will be :

30t = 50(t - 1)

30t = 50t - 50

30t - 50t = -50

-20t = -50

t =

t = 2.5 hours

After 2.5 hours passenger train would overtake the freight train.

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3