If there is an 80% chance of rain and a 50% chance of wind and rain, what is the probability that it is windy, given that it is rainy? round your answer to the nearest percent.

The probability that it is windy, given that it is rainy is:

                             62.5%≈63%

Step-by-step explanation:

Let A denote the event that it will rain.

B denote the event that it is windy.

A∩B denote the event that it is rainy and windy.

Let P denote the probability of an event.

i.e. we have:

P(A)=0.80

( Since there are 80% chance of rain)

P(A∩B)=0.50

(Since there are 50% chance of wind and rain)

We are asked to find:

P(B|A)

We know that:

Hence, the probability in percent is:

                   62.5%≈63%

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question

you need to rotate this triangle about the origin 270 degrees clockwise to create the full square.