You roll a number cube numbered from 1 to 6. What id the probability that the number is a 3

1 / 6

Step-by-step explanation:

S = { 1, 2, 3, 4, 5, 6 }

n ( S ) = 6

Let A be the event of getting the number " 3 ".

A = { 3 }

n ( A ) = 1

P ( A ) = n ( A ) / n ( S )

P ( A ) = 1 / 6

Therefore,

the probability that the number 3 is 1 / 6.

idk

step-by-step explanation: