Can someone help me with this is too hard for me. If the angle at the top of the tower is known, a surveyor would use the . function9 to find the length x.

The cosine of a 50° angle is a1 this represents the value created when length is divided by feet.

If the angle near the top of the tower was changed to 60°, the cosine would be 0.5; now the length of x would be feet.

If the angle near the top of the tower was changed to 60°, the angle from the light and the ground would be degrees.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

a

step-by-step explanation:

its wrong

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )