Mathematics, 21.04.2021 01:00 erikagibson3414
The perimeter of a rectangle is 120 m and the length is 50 m long than the width period find the dimensions of the rectangle. Let X equal the link and Y equals the width period the corresponding model system is 2X plus 2Y equals 120 and X minus Y equals 50. Solve the system graphically
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The perimeter of a rectangle is 120 m and the length is 50 m long than the width period find the dim...
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