In the diagram, two parallel lines are intersected by a transversal. What are the measurements of angles, 1, 2, 4, 5, 6, 7, and 8?

1, 6, 8 are each 55 degrees

2, 4, 5, 7 are each 125 degrees.

Step-by-step explanation:

We know 3 things that apply here:

1) When parallel lines are intersected by a transversal, the corresponding angles have the same measure. (the angles in the same position on the parallel line...2 and 4 are equal, 5 and 7 are equal, etc)

2)  Two angles that form a straight line equal 180 degrees

3) Angles that are opposite each other (vertical angles) in this situation are equal. (1 & 6 are equal, 4 & 7 are equal)

So what would be angle #3 is 55 degrees. That means the supplemental angle, #4 is 125 degrees.

Which makes angle 7 125 degrees and angle 8 55 degrees.

And then you apply these rules for angles 1, 2, 5 and 6.

Please let me know if you have any questions.

answer: 7270

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2