PLEASE ANSWER What is the sum of the n terms of the series 4 + 12 + 36 + 108 + . . . ? Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio. (4 points)

Sn = −2(2n − 1)
Sn = 2(3n − 1)
cap s sub n equals start fraction n over two end fraction left parenthesis four plus three n right parenthesis
cap s sub n equals start fraction four left parenthesis three to the power of n end power minus one right parenthesis over n minus one end fraction